Thursday, July 6, 2023

 

Problem Statement: A 0-indexed integer array nums is given.

Swaps of adjacent elements are able to be performed on nums.

A valid array meets the following conditions:

·       The largest element (any of the largest elements if there are multiple) is at the rightmost position in the array.

·       The smallest element (any of the smallest elements if there are multiple) is at the leftmost position in the array.

Return the minimum swaps required to make nums a valid array.

 

Example 1:

Input: nums = [3,4,5,5,3,1]

Output: 6

Explanation: Perform the following swaps:

- Swap 1: Swap the 3rd and 4th elements, nums is then [3,4,5,3,5,1].

- Swap 2: Swap the 4th and 5th elements, nums is then [3,4,5,3,1,5].

- Swap 3: Swap the 3rd and 4th elements, nums is then [3,4,5,1,3,5].

- Swap 4: Swap the 2nd and 3rd elements, nums is then [3,4,1,5,3,5].

- Swap 5: Swap the 1st and 2nd elements, nums is then [3,1,4,5,3,5].

- Swap 6: Swap the 0th and 1st elements, nums is then [1,3,4,5,3,5].

It can be shown that 6 swaps is the minimum swaps required to make a valid array.

Example 2:

Input: nums = [9]

Output: 0

Explanation: The array is already valid, so we return 0.

 

Constraints:

·         1 <= nums.length <= 105

·         1 <= nums[i] <= 105

Solution:

class Solution {

    public int minimumSwaps(int[] nums) {

        int min = Arrays.stream(nums).min().getAsInt();

        int max = Arrays.stream(nums).max().getAsInt();

        int count = 0;

        while (nums[0] != min && nums[nums.length-1] != max && count < 2 * nums.length) {           

            var numsList = Arrays.stream(nums).boxed().collect(Collectors.toList());

            var end = numsList.lastIndexOf(max);

            for (int i = end; i < nums.length-1; i++) {

                swap(nums, i, i+1);

                count++;

            }

 

            numsList = Arrays.stream(nums).boxed().collect(Collectors.toList());

            var start = numsList.indexOf(min);

            for (int j = start; j >= 1; j--) {

                swap(nums, j, j-1);

                count++;

            }

        }

 

        return count;

    }

 

    public void swap (int[] nums, int i, int j) {

        int temp = nums[j];

        nums[j] = nums[i];

        nums[i] = temp;

    }

}

 

Input

nums =

[3,4,5,5,3,1]

Output

6

Expected

6

 

Input

nums =

[9]

Output

0

Expected

0

 

 

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